四次三項(xiàng)式
則-(a-1)x^3,(b+3)x,-a中有兩項(xiàng)是0
所以-(a-1)=0,b+3=0
或a=0,b+3=0
所以a=1,b=-3或a=0,b=-3
如果多項(xiàng)式x^4-(a-1)x^3+5x^2+(b+3)x-a是關(guān)于x的四次三項(xiàng)式,求a,b
如果多項(xiàng)式x^4-(a-1)x^3+5x^2+(b+3)x-a是關(guān)于x的四次三項(xiàng)式,求a,b
數(shù)學(xué)人氣：692 ℃時(shí)間：2020-05-10 07:25:47
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