F(1-X)=1-F(X),當(dāng)x=0,可得 F(1)=1-F(0)=1
F(1-X)=1-F(X),當(dāng)x=1/2,可得 F(1/2)=1-F(1/2) 可得F(1/2)=1/2
F(X/3)=1/2F(X),當(dāng)x=1,可得 F(1/3)=1/2F(1),可得F(1/3)=1/2
F(X/3)=1/2F(X),當(dāng)x=1/2,可得 F(1/6)=1/2F(1/2),=1/4
F(X/3)=1/2F(X),當(dāng)x=1/3,可得 F(1/9)=1/2F(1/3),=1/4
由在[0,1]上當(dāng)x1
函數(shù)f(x)的定義域為d,若對任意x1,x2屬于d,當(dāng)x1
函數(shù)f(x)的定義域為d,若對任意x1,x2屬于d,當(dāng)x1
數(shù)學(xué)人氣:493 ℃時間:2020-01-29 21:23:05
優(yōu)質(zhì)解答
我來回答
類似推薦
- 函數(shù)f(x)的定義域為d,若對任意x1,x2屬于d,當(dāng)x1
- 函數(shù)f(x)的定義域為D,若對于任意x1、x2∈D,當(dāng)x1<x2時,都有f(x1) ≤f(x2),則稱函數(shù)f(x)在D上為非減函
- 函數(shù)f(x)的定義域為D,若對任意x1,x2∈D,當(dāng)x1<x2時,都有f(x1)≤f(x2),則稱函數(shù)f(x)在D上為非減函數(shù),
- 已知函數(shù)f(x)的定義域為R且對任意實數(shù)x1,x2.,總有f(x1+x2)+f(x1-x2)=2f(x1)f(x2)成立,求證:f(x)是偶函
- 函數(shù)f(x)的定義域為D,若對于任意x1,x2∈D,當(dāng)x1<x2時,都有f(x1)≤f(x2),則稱函數(shù)f(x)在D上為非減函數(shù)
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()