∴AD>4,AB<2,
根據(jù)題意,可分為以下兩種情況:
第一種情況,如圖1,
當(dāng)tan∠BAE=
1 |
2 |
則AB=DC=2m,AD=m+x,
∵AB+AD=6,
∴2(2m+m+x)=12,
m=
6-x |
3 |
S梯形AECD=
1 |
2 |
=
1 |
2 |
=m(m+2x),
=
6-x |
3 |
6+5x |
3 |
=-
5 |
9 |
8 |
3 |
6-x |
3 |
6-x |
3 |
∴x<6,x>3,
![](http://hiphotos.baidu.com/zhidao/pic/item/b58f8c5494eef01fd46f8974e3fe9925bc317d0c.jpg)
∴x的取值范圍是3<x<6;
第二種情況,如圖2,
tan∠AEB=
1 |
2 |
設(shè)CE=x,AB=CD=n,
則BE=2n,AD=2n+x,
∵矩形的周長(zhǎng)為12,
∴AB+AD=6,
∴2(n+2n+x)=12,n=
6-x |
3 |
S梯形AECD=
1 |
2 |
=
1 |
2 |
=n(n+x),
=
6-x |
3 |
6+2x |
3 |
=-
2 |
9 |
2 |
3 |
∵
6-x |
3 |
6-x |
3 |
∴x<6,x>0,
∴x的取值范圍是0<x<6.