答案是4a吧,
設(shè)出直線方程Y＝BX＋1/4
然后與拋物線方程聯(lián)立得PQ＝d
再求出PF,QF
1/P＋1/Q＝（P＋Q）/PQ
過拋物線y=ax^2(a>0)的焦點作一條直線交拋物線于P,Q兩點,若線段PF與FQ的長分別是P,q,則1/P+1/q=
過拋物線y=ax^2(a>0)的焦點作一條直線交拋物線于P,Q兩點,若線段PF與FQ的長分別是P,q,則1/P+1/q=
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