設(shè)F(X)是可導的偶函數(shù),且f'(0#存在.證明f'#0#=0求大神幫助
設(shè)F(X)是可導的偶函數(shù),且f'(0#存在.證明f'#0#=0求大神幫助
數(shù)學人氣:596 ℃時間:2020-05-24 09:25:08
優(yōu)質(zhì)解答
偶函數(shù)可導,導數(shù)一定是奇函數(shù).證明:f(-x)=f(x),則【f(-x)】’=f’(-x)*(-x)’= -1*f’(-x)=f’(x),所以f’(-x)= -f’(x),f’(x)是奇函數(shù),則若f’(0)存在,奇函數(shù)是過原點的,所以f’(0)=0
我來回答
類似推薦
- 如果f(x)為偶函數(shù),且f'(x)存在.證明:f'(x)=0.
- 如果f(x)為偶函數(shù),且f'(0)存在,證明f'(0)=0
- 設(shè)f(x)是偶函數(shù),且f‘(0)存在,證明f'(0)=0
- 如果f(x)為偶函數(shù).且f `(0)存在,證明 f ` (0) = 0
- 證明:f(x)是偶函數(shù)且f'(0)存在,則f'(0)=0
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()