a,b均為正實(shí)數(shù),求證:根號(hào)(a/(a+3b))+根號(hào)(b/(b+3a))≥1
a,b均為正實(shí)數(shù),求證:根號(hào)(a/(a+3b))+根號(hào)(b/(b+3a))≥1
數(shù)學(xué)人氣:683 ℃時(shí)間:2020-06-05 07:14:32
優(yōu)質(zhì)解答
設(shè)x=根號(hào)(a/(a+3b))+根號(hào)(b/(b+3a)),則x^2=(3a^2+3b^2+2ab)/(3a^2+10ab+3b^2)+2根號(hào)(ab/(3a^2+10ab+3b^2)),設(shè)y=根號(hào)(ab/(3a^2+10ab+3b^2)=根號(hào)(ab/(3a^2+3b^2+10ab),其中3a^2+3b^2+10ab=3(a^2+b^2)>=6ab+10ab=16ab,...
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