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  • y=sinx+cosx+sinxcosx+1的最值

    y=sinx+cosx+sinxcosx+1的最值
    其他人氣:228 ℃時(shí)間:2020-02-01 03:07:48
    優(yōu)質(zhì)解答
    y = sinx+cosx+sinxcosx+1
    y' = cosx - sinx - (sinx)^2 + (cosx)^2
    = (cosx+1/2)^2- (sinx+1/2)^2
    = (cosx+sinx+1)(cosx-sinx)
    y' =0
    => sinx = cosxor cosx+sinx+1=0
    => tanx = 1orsin(π/4 +x ) = -√2/2
    => x = π/4 orx = π
    max y , at x= π/4
    max y = sinπ/4 + cosπ/4 + sinπ/4cosπ/4 + 1
    = √2/2+√2/2+(√2/2)√2/2+1
    = 3/2+ √2
    miny,at x=π
    miny = sinπ + cosπ+ sinπcosπ+1
    = 0-1+(-1).0+1
    = 0
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