cos(xy)+x^6=y^6
兩邊同時(shí)對(duì)x求導(dǎo)得
-sin(xy)·(xy) '+6x^5=6y^5·y'
-sin(xy)·(y+xy ')+6x^5=6y^5·y'
得y '=[6x^5-ysin(xy)]/[6y^5+xsin(xy)]為什么會(huì)有-sin(xy)·(y+xy ')+6x^5=6y^5·y'這步出現(xiàn)??？-sin(xy)·(xy) '+6x^5=6y^5·y'→這步看懂了嗎等等...-sin(xy)·(xy) '+6x^5=6y^5·y'-sin(xy)·(y+xy ')+6x^5=6y^5·y'這一步中的y+xy '是上面的xy求導(dǎo)得到的，其他的一樣 注意(xy) '=y+xy '嗯看懂了...最后一步呢？最后一步是就是上面一步化簡(jiǎn)合并同類項(xiàng)，得到y(tǒng) '想了半天，結(jié)果不應(yīng)該是y'=[-sin(xy)·(y+xy ')+6x^5]/[6y^5]嗎？怎么算出y '=[6x^5-ysin(xy)]/[6y^5+xsin(xy)]的？-ysin(xy)-xy 'sin(xy)+6x^5=6y^5·y'6y^5·y'+xy 'sin(xy)=6x^5-ysin(xy)[6y^5+xsin(xy)]y '=6x^5-ysin(xy)y'=[6x^5-ysin(xy)]/[6y^5+xsin(xy)] 請(qǐng)選為滿意回答把