∴HM=ND=50-40cosθ.AM=50-40sinθ.
∴S=(50-40cosθ)(50-40sinθ)
=100[25-20(sinθ+cosθ)+16sinθcosθ],(0≤θ≤
π |
2 |
![](http://hiphotos.baidu.com/zhidao/pic/item/55e736d12f2eb9381652bc43d6628535e5dd6f40.jpg)
令t=sinθ+cosθ=
2 |
π |
4 |
則sinθcosθ=
t2-1 |
2 |
2 |
∴S=100[25-20t+8(t2-1)]
=800(t-
5 |
4 |
又∵t∈[1,
2 |
∴當(dāng)t=1時(shí),S取最大值500.
此時(shí),
2 |
π |
4 |
∴sin(θ+
π |
4 |
| ||
2 |
∵
π |
4 |
π |
4 |
3π |
4 |
∴θ+
π |
4 |
π |
4 |
3π |
4 |
即θ=0或θ=
π |
2 |
答:當(dāng)點(diǎn)H在
![]() |
EF |