若單項(xiàng)式5x^2y和42x^my^n是同類項(xiàng),那么m+n的值
若單項(xiàng)式5x^2y和42x^my^n是同類項(xiàng),那么m+n的值
若多項(xiàng)式2x^3-8x^2+x-1與多項(xiàng)式3x^3+2mx^2-5x+3的和不含二次項(xiàng),則m等于多少?
已知14x^5y^2和-1/3x^3m y^2是同類項(xiàng),則12m-24的值是多少?
注:-1/3x^3m的3m是一體
若多項(xiàng)式2x^3-8x^2+x-1與多項(xiàng)式3x^3+2mx^2-5x+3的和不含二次項(xiàng),則m等于多少?
已知14x^5y^2和-1/3x^3m y^2是同類項(xiàng),則12m-24的值是多少?
注:-1/3x^3m的3m是一體
數(shù)學(xué)人氣:877 ℃時間:2019-08-27 08:08:11
優(yōu)質(zhì)解答
同類項(xiàng)的定義:所含字母相同,并且相同字母的指數(shù)也分別相同的項(xiàng)叫做同類項(xiàng).
………………………………………………………
若單項(xiàng)式5x^2y和42x^my^n是同類項(xiàng),則
2=m,1=n
∴m+n=3
……………………………………………………
若多項(xiàng)式2x^3-8x^2+x-1與多項(xiàng)式3x^3+2mx^2-5x+3的和不含二次項(xiàng),則
(2x³-8x²+x-1)+(3x³+2mx²-5x+3)
=5x³+(-8+2m)x²-4x+2
不含二次項(xiàng),就是說二次項(xiàng)系數(shù)是0,
∴-8+2m=0
∴m=4
……………………………………………………
14x^5y^2和-1/3x^(3m) y^2是同類項(xiàng),則
5=3m,2=2
∴m=5/3
∴12m-24=12*(5/3)-24=20-24=-4
謝謝
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