若函數(shù)f(x)=loga(2x+1)(a>0,且a≠1)在區(qū)間(-12,0)內(nèi)恒有f(x)>0,則f(x)的單調(diào)減區(qū)間是( ?。?A.(-∞,-12) B.(-12,+∞) C.(-∞,0) D.(0,+∞)
若函數(shù)f(x)=loga(2x+1)(a>0,且a≠1)在區(qū)間(-
,0)內(nèi)恒有f(x)>0,則f(x)的單調(diào)減區(qū)間是( )
A. (-∞,-
)
B. (-
,+∞)
C. (-∞,0)
D. (0,+∞)
1 |
2 |
A. (-∞,-
1 |
2 |
B. (-
1 |
2 |
C. (-∞,0)
D. (0,+∞)
數(shù)學(xué)人氣:836 ℃時(shí)間:2020-05-09 18:36:14
優(yōu)質(zhì)解答
函數(shù)f(x)=loga(2x+1)的定義域?yàn)椋?12,+∞),當(dāng)x∈(-12,0)時(shí),2x+1∈(0,1),∴0<a<1,∵函數(shù)f(x)=loga(2x+1)(a>0,a≠1)由f(x)=logat和t=x+1復(fù)合而成,0<a<1時(shí),f(x)=logat在(0,+∞)上...
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