1 |
n |
1 |
p |
1 |
m |
1 |
p |
1 |
m |
1 |
n |
m |
n |
m |
p |
n |
m |
n |
p |
p |
m |
p |
n |
m?p |
n |
n?p |
m |
m+n |
p |
由題意可得:m-p=-n,m-p=-n,n-p=-m,m+n=p,
∴可得:m(
1 |
n |
1 |
p |
1 |
m |
1 |
p |
1 |
m |
1 |
n |
故答案為:-3.
1 |
n |
1 |
p |
1 |
m |
1 |
p |
1 |
m |
1 |
n |
1 |
n |
1 |
p |
1 |
m |
1 |
p |
1 |
m |
1 |
n |
m |
n |
m |
p |
n |
m |
n |
p |
p |
m |
p |
n |
m?p |
n |
n?p |
m |
m+n |
p |
1 |
n |
1 |
p |
1 |
m |
1 |
p |
1 |
m |
1 |
n |