令和為N,當(dāng)x=1時(shí),N=2+3+……+n=(n+3)n/2;
當(dāng)x≠1時(shí),xN=2x^3+……+nx^(n+1)
(x-1)N
=nx^(n+1)-(x^3+x^4+……+x^n)-2x^2
=nx^(n+1)-x^3(1-n^(n-2))/(1-x)-2x^2
N=(nx^(n+1)-x^3(1-n^(n-2))/(1-x)-2x^2)/(x-1)
求數(shù)列2x^2,3x^3,4X^4,...,nX^n,...的前n項(xiàng)和
求數(shù)列2x^2,3x^3,4X^4,...,nX^n,...的前n項(xiàng)和
過(guò)程
過(guò)程
數(shù)學(xué)人氣:158 ℃時(shí)間:2020-04-23 11:42:25
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