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  • x^4+x^3+2x^2+x+1

    x^4+x^3+2x^2+x+1
    -1-2x-x^2+y^2
    x^2+ax^2+x+ax-1-a
    x^3-2x^2-x+2+x^5-2x^4
    x^3+x^2-y^3-y^2
    ab(c^2-d^2)-(a^2-d^2)cd
    x^8-y^8
    2(x+y)+6(x+y)^2-4(x+3)^3
    -(3a^2-5b^2)^2+(5a^2-3b^2)^2
    (5x^2+2x-3)^2-(x^2-2x-3)^2
    x^2(a+b)^2-2xy(a^2-b^2)+y(a-b)^2
    9a^2+x^2n+6a+2x^n+6ax^n+1
    數(shù)學(xué)人氣:353 ℃時(shí)間:2020-03-21 22:17:39
    優(yōu)質(zhì)解答
    x^4+x^3+2x^2+x+1
    =x^4+x^3+x^2+x^2+x+1
    =x^2(x^2+x+1)+x^2+x+1
    =(x^2+1)(x^2+x+1)
    -1-2x-x^2+y^2
    =y^2-(1+2x+x^2)
    =y^2-(x+1)^2
    =(y+x+1)(y-x-1)
    x^2+ax^2+x+ax-1-a
    =x^2(a+1)+x(a+1)-(a+1)
    =(a+1)(x^2+x-1)
    x^3-2x^2-x+2+x^5-2x^4
    =x^5-2x^4+x^3-2x^2-x+2
    =x^4(x-2)+x^2(x-2)-(x-2)
    =(x-2)(x^4+x^2-1)
    x^3+x^2-y^3-y^2
    =x^3-y^3+x^2-y^2
    =(x-y)(x^2+x+1)+(x+y)(x-y)
    =(x-y)(x^2+x+1+x+y)
    =(x-y)(x^2+2x+y+1)
    ab(c^2-d^2)-cd(a^2-b^2)
    =abc^2-abd^2-a^2cd+b^2cd
    =(abc^2-a^2cd)-abd^2+b^2cd
    =ac(bc-ad)+bd(bc-ad)
    =(bc-ad)(ac+bd)
    x^8-y^8
    =(x^4+y^4)(x^4-y^4)
    =(x^4+y^4)(x^2+y^2)(x^2-y^2)
    =(x^4+y^4)(x^2+y^2)(x+y)(x-y)
    2(x+y)+6(x+y)^2-4(x+3)^3
    =2(x+y)[1+3(x+y)-4(x+y)^2]
    =2(x+y)[1-4(x+y)][1+(x+y)]
    =2(x+y)(1-4x-4y)(1+x+y)
    -(3a^2-5b^2)^2+(5a^2-3b^2)^2
    =(5a^2-3b^2)^2-(3a^2-5b^2)^2
    =[(5a^2-3b^2)-(3a^2-5b^2)][(5a^2-3b^2)+(3a^2-5b^2)]
    =(2a^2+2b^2)(8a^2-8b^2)
    =16(a^2+b^2)(a+b)(a-b)
    (5x^2+2x-3)^2-(x^2-2x-3)^2
    =(5x^2+2x-3)^2-(x^2-2x-3)^2
    =[(5x^2+2x-3)-(x^2-2x-3)][(5x^2+2x-3)+(x^2-2x-3)]
    =(6x^2+4x)(6x^2-6)
    =12x(3x+2)(x+1)(x-1)
    x^2(a+b)^2-2xy(a^2-b^2)+y^2(a-b)^2
    =[x(a+b)-y(a-b)]^2
    9a^2+x^2n+6a+2x^n+6ax^n+1
    =x^2n+6ax^n+9a^2+6a+2x^n+1
    =(x^n+3a)^2+2(x^n+3)+1
    =(x^n+3a+1)^2
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