令3x+π/4=t
(sin^3t)'=((sin^2t)(sint))'
利用求導(dǎo)乘法法則
=（sin^2t)'sint+(sint)'sin^2t
對(duì)sin^2t再利用求導(dǎo)法則,得到
=(sint(sint)'+(sint)'sint)sint+costsin^2t
=(2sintcost)sint+costsin^2t
=2sin^2tcost+costsin^2t
=3costsin^2t
帶入t=3x+π/4
=3cos(3x+π/4)sin^2(3x+π/4)
y=sin³（3x+π/4）的導(dǎo)數(shù)
y=sin³（3x+π/4）的導(dǎo)數(shù)
數(shù)學(xué)人氣：380 ℃時(shí)間：2019-09-17 15:49:20
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