y=(x-2)(x+2)/(x-2)(x-3)
lim{x->2}(x-2)(x+2)/(x-2)(x-3)=lim{x->2}(x+2)/(x-3)=(2+2)/(2-3)=-4,所以x=2是可去間斷點(diǎn).當(dāng)x=2時(shí),令y=-4,則函數(shù)在x=2處連續(xù)
lim{x->3}(x-2)(x+2)/(x-2)(x-3)=lim{x->2}(x+2)/(x-3)=∞,所以x=3是第二類間斷點(diǎn)中的無窮間斷點(diǎn)
y=(x^2-4)/(x^2-5x+6) 在x=2,x=3處間斷,說明間斷點(diǎn)的類型,如果是可去間斷點(diǎn),補(bǔ)充或改變函數(shù)的定義使它連續(xù)
y=(x^2-4)/(x^2-5x+6) 在x=2,x=3處間斷,說明間斷點(diǎn)的類型,如果是可去間斷點(diǎn),補(bǔ)充或改變函數(shù)的定義使它連續(xù)
數(shù)學(xué)人氣：496 ℃時(shí)間：2019-11-24 19:19:44
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