=2sin²x+2sinxcosx
=1-cos(2x)+sin(2x)
=√2sin(2x-π/4)+1
當(dāng)2kπ-π/2≤2x-π/4≤2kπ+π/2,k∈Z
即kπ-π/8≤x≤kπ+3π/8,k∈Z時(shí),f(x)為增函數(shù);
當(dāng)2kπ+π/2<2x-π/4<2kπ+3π/2,k∈Z
即kπ+3π/8<x<kπ+7π/8,k∈Z時(shí),f(x)為減函數(shù),
∴函數(shù)的增區(qū)間為[kπ-π/8,kπ+3π/8],減區(qū)間為(kπ+3π/8,kπ+7π/8),k∈Z.
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