7-Q11:
x是正整數(shù)
問:[(3^x)+1]/10的余數(shù)是否為0?
statement (1): x = 4n + 2,其中n是正整數(shù)
3^x的個位數(shù)即為(3^x)/10的余數(shù)
由上表可知,3^x的個位數(shù)的周期為4,即(3^x)/10的余數(shù)的周期為4
因此,x=4n+2時,(3^x)/10的余數(shù)為9, [(3^x)+1]/10的余數(shù)為0,SUFF
statement (2): x>4, [(3^x)+1]/10的余數(shù)有多種可能,INSUFF
選A