xy=3-2=1
x+y=2√3
平方
x²+2xy+y²=12
所以x²+y²=12-2xy=10
所以原式=3(x²+y²)-√xy
=30-1
=29不好意思了,謝謝阿
已知,x=√3+√2,y=√3-√2,求3x²-√xy+3y³
已知,x=√3+√2,y=√3-√2,求3x²-√xy+3y³
急.在線等
急.在線等
數(shù)學(xué)人氣:492 ℃時(shí)間:2019-08-22 12:27:56
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