y=cos(x+π/2)+sin(π/3-x)的最大值是...
y=cos(x+π/2)+sin(π/3-x)的最大值是...
答案是根號(hào)3 急 明天開學(xué)
答案是根號(hào)3 急 明天開學(xué)
數(shù)學(xué)人氣：234 ℃時(shí)間：2020-06-13 07:03:22
優(yōu)質(zhì)解答
y=cos(x+π/2)+sin(π/3-x)=-sinx+sinπ/3cosx-cosπ/3sinx=-sinx+√3/2cosx-1/2sinx=√3/2cosx-3/2sinx=√3(1/2cosx-√3/2sinx)=√3cos(x+π/3)因?yàn)閏os(x+π/3)∈[-1,1]所以√3cos(x+π/3)∈[-√3,√3]所以y=cos(x+...
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