sin2α = sin(α+α) = sinαcosα + cosαsinα= 2sinαcosα
余弦二倍角公式:
余弦二倍角公式有三組表示形式,三組形式等價(jià):
1.cos2α = 2cos^2 α- 1
2.cos2α = 1 − 2sin^2 α
3.cos2α = cos^2 α − sin^2 α
推導(dǎo):
cos2A = cos(A+A) = cosAcosA - sinAsinA = cos^2 A- sin^2 A = 2cos^2 A - 1=1 - 2sin^2 A
正切二倍角公式:
tan2α = 2tanα/[1 - (tanα)^2]
tan(1/2*α)=(sin α)/(1+cos α)=(1-cos α)/sin α
推導(dǎo):
tan(2a) = tan(a+a) = (tan(a) + tan(a))/(1 - tan(a)*tan(a) )= 2tanα/[1 - (tanα)^2]
具體推導(dǎo)二倍角公式
具體推導(dǎo)二倍角公式
數(shù)學(xué)人氣:897 ℃時(shí)間:2020-04-29 16:26:06
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