m∥n,即：a/ainB=b/sinA
即：asinA=bsinB,即：a^2=b^2,即：a=b
故：A=B=π/3
2
m⊥p,即：m·p=(a,b)·(b-2,a-2)
=ab-2a+ab-2b=2ab-2a-2b=0
即：a+b=ab
S=(1/2)absinC=√3ab/4=√3
即：ab=4,即：a+b=4
c^2=a^2+b^2-2abcosC=a^2+b^2-ab
=(a+b)^2-3ab=16-12=4
即：c=2童鞋你看我的題了沒(méi)？