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  • 1/1*2*3+1/2*3*4+1/3*4*5+...1/98*99*100如何計算

    1/1*2*3+1/2*3*4+1/3*4*5+...1/98*99*100如何計算
    數(shù)學人氣:700 ℃時間:2019-10-19 17:12:15
    優(yōu)質(zhì)解答
    1/(1*2*3)+1/(2*3*4)+1/(3*4*5)+……+1/(98*99*100)
    =(1/2)*(4-3)/(3*4)+(1/3)*(5-4)/(4*5)+(1/4)*(6-5)/(5*6)+……+(1/98)*(100-99)*(99*100)
    =(1/2)*(1/3-1/4)+(1/3)*(1/4-1/5)+(1/4)*(1/5-1/6)+……+(1/98)*(1/99-1/100)
    =(1/2)*(1/3)-(1/2)*(1/4)+(1/3)*(1/4)-(1/3)*(1/5)+(1/4)*(1/5)-(1/4)*(1/6)+……+(1/98)*(1/99)-(1/98)*(1/100)
    =[(1/2)*(1/3)+(1/3)*(1/4)+(1/4)*(1/5)+.+(1/98)*(1/99)]-[(1/2)(1/4)+(1/3)*(1/5)+(1/4)*(1/6)+.+(1/98)*(1/100)]
    =[(3-2)/(2*3)+(4-3)/(3*4)+(5-4)/(4*5)+.+(99-98)/(98*99)]-(1/2)[(4-2)/(2*4)+(5-3)/(3*5)+(6-4)/(4*6)+.+(100-98)/(98*100)]
    =[1/2-1/3+1/3-1/4+1/4-1/5+.+1/98-1/99]-(1/2)[1/2-1/4+1/3-1/5+1/4-1/6+1/5-1/7.+1/96-1/98+1/97-1/99+1/98-1/100]
    =[1/2-1/99]-(1/2)[1/2-1/99-1/100]
    =1/2-1/99-1/4+1/198+1/200
    =(1/2-1/99+1/198)+1/200-1/4
    =49/99-49/200
    =(200*49-99*49)/(99*200
    =101*49/(99*200)
    =4949/19800
    由于時間倉促,最后兩步約分可以有誤,望原諒.
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