sin^4a+cos^4a
=(sin²a+cos²a)²-2sin²acos²a
=1-(1/2)sin²2a
=1-(1/2)[1-cos²2a]
=1-(1/2)[1-(2/9)]
=11/18
這樣可以么?
已知cos2θ=根號2/3,則 sin^4θ+cos^4θ的值為________.
已知cos2θ=根號2/3,則 sin^4θ+cos^4θ的值為________.
sin^4a+cos^4a
=(sin²a+cos²a)²-2sin²acos²a
=1-(1/2)sin²2a
=1-(1/2)[1-cos²2a]
=1-(1/2)[1-(2/9)]
=11/18
2sin²acos²a=2{(2sina cosa)/2}²
這樣?.還是啥意思.2sin²acos²a=sin ² 2a?那為什么前面又要1/2.沒搞懂.
sin^4a+cos^4a
=(sin²a+cos²a)²-2sin²acos²a
=1-(1/2)sin²2a
=1-(1/2)[1-cos²2a]
=1-(1/2)[1-(2/9)]
=11/18
2sin²acos²a=2{(2sina cosa)/2}²
這樣?.還是啥意思.2sin²acos²a=sin ² 2a?那為什么前面又要1/2.沒搞懂.
數(shù)學(xué)人氣:330 ℃時間:2019-10-24 09:09:15
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