y=√3sinx-cosx =-2[cosx*(1/2)-sinx*(√3/2)] =-2[cosxcos(π/3)-sinxsin(π/3)]=-2cos(x+π/3)圖像向右平移π/3個(gè)單位,成為偶函數(shù)注意到y(tǒng)=-2cos(x+π/3)的周期是2π,所以,向左平移π-π/3=2π/3,也是偶函數(shù)所以m...換成以sin開頭的可以嗎？y=-2sin(x+5π/6）圖象向左平移m個(gè)單位，是偶函數(shù)則0=-2sin(0+5π/6+m） 5π/6+m=kπ m=-5π/6+kπ又m＞0所以m最小=π/6?????????3???2?? ????? 6????У???????????????/60=-2cos(0+??/3+m????/3+m=??/2+k??m=??/6+k??m??С???=??/6那個(gè)0是啥意思？因?yàn)樗桥己瘮?shù)，所以坐標(biāo)（0,0）代入符合題意