設(shè)α為第二象限的角,sinα=3/5,求sin(37π6?2α)的值.
設(shè)α為第二象限的角,
sinα=,求
sin(?2α)的值.
優(yōu)質(zhì)解答
因?yàn)?span>sin(
?2α)=sin(
?2α),
sinα=?cosα=?(α為Ⅱ)
sin2α=?cos2α=1?2sin2α=-------(6分)
所以
sin(?2α)=---------------(13分)
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