令x=1
左=(2x+1)^100=3^100
右=a0+a1x+a2x^2……+a100x^100=a0+a1+a2+.+a100
因此,a0+a1+a2+.+a100=3^100
若(2x+1)^100=a0+a1x+a2x^2……+a100x^100求a0+a1+a2+.+a100=?
若(2x+1)^100=a0+a1x+a2x^2……+a100x^100求a0+a1+a2+.+a100=?
數(shù)學(xué)人氣:710 ℃時(shí)間:2020-05-22 18:56:22
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