求證(1-sinθcosθ)除以(cos^2θ-sin^2θ)=(cos^2θ-sin^2θ)除以(1+2sinθcosθ)
求證(1-sinθcosθ)除以(cos^2θ-sin^2θ)=(cos^2θ-sin^2θ)除以(1+2sinθcosθ)
數(shù)學(xué)人氣:236 ℃時(shí)間:2020-04-04 11:38:39
優(yōu)質(zhì)解答
是 (1 -2 sin θ cos θ) /[ (cos θ)^2 -(sin θ)^2 ] = [ (cos θ)^2 -(sin θ)^2 ] / (1 +2 sin θ cos θ) = = = = = = = = =證明:因?yàn)?(cos θ)^2 -(sin θ)^2 =(cos θ +sin θ) (cos θ -sin θ),1 -2 sin ...
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