等差數(shù)列{An}各項(xiàng)均為正整數(shù),A1=3.前n項(xiàng)和為Sn.等比數(shù)列{Bn}中,B1=1且B2S2=64.{Ban}是公比為64的等比...
等差數(shù)列{An}各項(xiàng)均為正整數(shù),A1=3.前n項(xiàng)和為Sn.等比數(shù)列{Bn}中,B1=1且B2S2=64.{Ban}是公比為64的等比...
等差數(shù)列{An}各項(xiàng)均為正整數(shù),A1=3.前n項(xiàng)和為Sn.等比數(shù)列{Bn}中,B1=1且B2S2=64.{Ban}是公比為64的等比數(shù)列,求An與Bn
等差數(shù)列{An}各項(xiàng)均為正整數(shù),A1=3.前n項(xiàng)和為Sn.等比數(shù)列{Bn}中,B1=1且B2S2=64.{Ban}是公比為64的等比數(shù)列,求An與Bn
數(shù)學(xué)人氣:535 ℃時(shí)間:2019-11-02 03:10:12
優(yōu)質(zhì)解答
等差數(shù)列{an}各項(xiàng)均為正整數(shù),a1=3;設(shè)公差為d;an=a1+(n-1)d=3+(n-1)d;前n項(xiàng)和為Sn=3n+n(n-1)d/2;等比數(shù)列{bn}中,b1=1;設(shè)公比為q;bn=b1q^(n-1)=q^(n-1);b2S2=64;q*(6+d)=64;ban=q^(an-1)=q^[2+(n-1)d];ba(n-1)=q^[a(n-...
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