題意要求用誘導(dǎo)公式:
sin(π/2+α)=cosα
sin(3π/2+3α)=-cos3α
sin(3π/2+3α)
=3sin(π/2+α)-4sin³(π/2+α) (已知sin3α=3sinα-4sin³α)
=3cosa-4cos³a
所以:cos3α=-(3cosa-4cos³a)=4cos³a-3cosa
已知sin3α=3sinα-4sin³α,怎么用誘導(dǎo)公式求出cos3α?
已知sin3α=3sinα-4sin³α,怎么用誘導(dǎo)公式求出cos3α?
數(shù)學(xué)人氣:498 ℃時間:2020-07-18 21:00:31
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