已知函數(shù)f(x)=a[2sin^2(x/2)+sinx]+b
已知函數(shù)f(x)=a[2sin^2(x/2)+sinx]+b
(1)當(dāng)a=1時(shí),求f(x)的單調(diào)遞減區(qū)間
(2)當(dāng)a
(1)當(dāng)a=1時(shí),求f(x)的單調(diào)遞減區(qū)間
(2)當(dāng)a
數(shù)學(xué)人氣:575 ℃時(shí)間:2020-04-02 23:06:50
優(yōu)質(zhì)解答
(1)由于f(x)=a[2sin^2(x/2)+sinx]+b= a[1-cosx+sinx]+b=a(sinx-cosx)+a+b=根2×a((根2/2)sinx-(根2/2)cosx)+a+b= 根2×a×sin(x-π/4)+a+b從而當(dāng)a=1時(shí),f(x)的單調(diào)遞減區(qū)間為:[2Kπ+(3π/4),2Kπ+(7π/4)](2) 當(dāng)a...
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