把直線y=4-2x繞著坐標原點向逆時針方向旋轉(zhuǎn)90°后得到的直線的函數(shù)解析式是?
把直線y=4-2x繞著坐標原點向逆時針方向旋轉(zhuǎn)90°后得到的直線的函數(shù)解析式是?
數(shù)學人氣:707 ℃時間:2020-04-18 12:37:32
優(yōu)質(zhì)解答
從原函數(shù)上隨便找一點如A(4,0),旋轉(zhuǎn)后它被轉(zhuǎn)到點B(0,4)則點必在所得直線上.因為逆時針旋轉(zhuǎn)九十度,故它們斜率之積為-1所以所得直線斜率k=0.5由點B及斜率k可求出其點斜式為y=0.5x+4
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