若是∫sin(α-β)dx=sin(α-β)x+c
若是∫sin(x-β)dx=∫sin(x-β)d(x-β)=-con(x-β)+c
∫sin(α-β)dx,(β≠0)
∫sin(α-β)dx,(β≠0)
數(shù)學(xué)人氣：957 ℃時(shí)間：2020-08-27 05:01:06
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