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  • ∫(0到-π)x sin(nx)dx=?

    ∫(0到-π)x sin(nx)dx=?
    如上,把sin(nx)改為cos(nx)=?5
    數(shù)學(xué)人氣:754 ℃時(shí)間:2020-07-10 07:32:00
    優(yōu)質(zhì)解答
    兩題都給你做下:
    ————————————————————————————————————
    ∫ xsin(nx) dx
    = (- 1/n)∫ x d[cos(nx)]
    = (- x/n)cos(nx) + (1/n)∫ cos(nx) dx
    = (- x/n)cos(nx) + (1/n^2)sin(nx) + C

    ∫(- π→0) xsin(nx) dx
    = (- x/n)cos(nx) + (1/n^2)sin(nx)_(x = 0) - (- x/n)cos(nx) + (1/n^2)sin(nx)_(x = - π)
    = (- π/n)cos(nπ)
    = - π/n,當(dāng)n為偶數(shù)
    = π/n,當(dāng)n為奇數(shù)
    ————————————————————————————————————
    ∫ xcos(nx) dx
    = (1/n)∫ x d[sin(nx)]
    = (x/n)sin(nx) - (1/n)∫ sin(nx) dx
    = (x/n)sin(nx) + (1/n^2)cos(nx) + C

    ∫(- π→0) xcos(nx) dx
    = (x/n)sin(nx) + (1/n^2)cos(nx)_(x = 0) - (x/n)sin(nx) + (1/n^2)cos(nx)_(x = - π)
    = (1/n^2)[1 - cos(nπ)]
    = 0,當(dāng)n為偶數(shù)
    = 2/n^2,當(dāng)n為奇數(shù)
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