設(shè)切線斜率為k,方程為y-2 = k(x-0),kx - y + 2 = 0圓x²+y²=1圓心為原點,半徑1原點與切線距離d等于半徑d = |k*0 -0+2|/√(k² + 1) = 2/√(k² + 1) = 1k = ±1二切線關(guān)于y軸對稱,下面只選一個(k =...算錯了，答案可是12/13第4行錯了，k = ±√3二切線關(guān)于y軸對稱，下面只選一個(k = √3)計算.切線:y = √3x + 2代入橢圓方程: x²/4 + (√3x+ 2)² = 113x² + 16√3x+ 12= 0x₁ = (-8√3 + 6)/13, x₂ = (-8√3 -6)/13y₁= √3x₁ + 2, y₂ = √3x₂ + 2A(-6/5, 4/5), B(-2,0)AB² = (x₁ - x₂)² + (y₁ - y₂)²= (x₁ - x₂)² + (√3x₁ + 2 - √3x₂ - 2)²= 4(x₁ - x₂)²= 4(12/13)²AB = 24/13三角形OAB的面積 = (1/2)*|AB|*d = (1/2)*(24/13)*1= 12/13