∫(1,-1) (|x|+sinx)x^2 dx
=∫(1,-1) |x|x^2 dx +∫(1,-1) sinxx^2 dx
=2∫(1,0) x^3 dx +0
=2*1/4
=1/22∫(1,0) x^3 dx +0請(qǐng)問這步是怎么推導(dǎo)出來的，謝謝。|x|x^2是偶函數(shù) sinxx^2是奇函數(shù)