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  • 已知函數(shù)y=sin(wx+Q)(w>0,絕對(duì)值Q>π/2)在同一周期內(nèi)

    已知函數(shù)y=sin(wx+Q)(w>0,絕對(duì)值Q>π/2)在同一周期內(nèi)
    已知函數(shù)f(x)=sin(wx+Q)(w>0,絕對(duì)值Q>π/2)在同一周期內(nèi),當(dāng)x=pai/4時(shí),y取最大值1,當(dāng)7pai/12時(shí),y取最小值-1
    ⑴求函數(shù)y=f(x)
    ⑵函數(shù)y=sinx的圖像經(jīng)過怎樣的變換可得到y(tǒng)=f(x)
    ⑶若函數(shù)f(x)滿足方程f(x)=(0<a<1),求在[0,2pai]內(nèi)所有實(shí)數(shù)根之和
    其他人氣:690 ℃時(shí)間:2020-01-19 21:50:32
    優(yōu)質(zhì)解答
    已知函數(shù)f(x)=sin(wx+Q)(w>0,絕對(duì)值Q>π/2)在同一周期內(nèi),當(dāng)x=pai/4時(shí),y取最大值1,當(dāng)7pai/12時(shí),y取最小值-1
    ⑴求函數(shù)y=f(x)
    ⑵函數(shù)y=sinx的圖像經(jīng)過怎樣的變換可得到y(tǒng)=f(x)
    ⑶若函數(shù)f(x)滿足方程f(x)=(0<a<1),求在[0,2pai]內(nèi)所有實(shí)數(shù)根之和
    (1)解析:∵函數(shù)f(x)=sin(wx+Q)(w>0,絕對(duì)值Q>π/2)在同一周期內(nèi),當(dāng)x=pai/4時(shí),y取最大值1,當(dāng)7pai/12時(shí),y取最小值-1
    ∴T/2=7π/12-π/4=π/3==>T=2π/3==>w=2π/T=3
    ∴f(x)=sin(3x+Q)==> f(π/4)=sin(3π/4+Q)=1==>3π/4+Q=π/2==>Q=-π/4
    ∴f(x)=sin(3x-π/4)
    (2)解析:函數(shù)y=sinx
    A:將函數(shù)y水平右移π/4單位得y=sin(x-π/4)
    B:將X軸坐標(biāo)單位水平壓縮到原單位的1/3,得y=sin(3x-π/4)

    A:將X軸坐標(biāo)單位水平壓縮到原單位的1/3,得y=sin(3x)
    B:將函數(shù)y水平右移π/12單位得y=sin(3(x-π/12))= sin(3x-π/4)
    (3)解析:方程f(x)=a(0<a<1)
    sin(3x-π/4)= √2/2==>3x-π/4=2kπ+π/4==>x=2kπ/3+π/6;3x-π/4=2kπ+3π/4==>x=2kπ/3+π/3
    sin(3x-π/4)=1/2==>3x-π/4=2kπ+π/6==>x=2kπ/3+5π/36;3x-π/4=2kπ+5π/6==>x=2kπ/3+13π/36
    sin(3x-π/4)= √3/2==>3x-π/4=2kπ+π/3==>x=2kπ/3+7π/36;3x-π/4=2kπ+4π/6==>x=2kπ/3+11π/36
    在[0,2pai]內(nèi)所有實(shí)數(shù)根之和
    π/6+2π/6+5π/6+6π/6+9π/6+10π/6=11π/2
    5π/36+13π/36+29π/36+37π/36+53π/36+61π/36=11π/2
    7π/36+11π/36+31π/36+35π/36+55π/36+59π/36=11π/2可見,無論a∈(0,1)取何值,在[0,2pai]內(nèi)所有實(shí)數(shù)根之和均為11π/2
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