設(shè)P(m,n) ,mn≠0
P在圓x^2+y^2=2上,m²+n²=2
那么過P點圓的切線與OP垂直,
斜率k=-m/n
∴L:y-n=-m/n(x-m)
即y=-m/nx+(m²+n²)/n
y=-m/nx+2/n
聯(lián)立方程組：
{y=(-mx+2)/n
{x²-y²/2=2
==>
x²-(2-mx)²/(2n²)=1
==>
(2n²-m²)x²+4mx-4-2n²=0
∵n²=2-m²
∴方程即
(4-3m²)x²+4mx+2m²-8=0
需4-3m²≠0
△=16m²+4(3m²-4)(2m²-8)>0
設(shè)A(x1,y1),B(x2,y2)
那么x1+x2=-4m/(4-3m²)
x1x2=(2m²-8)/(4-3m²)
∴OA·OB
=x1x2+y1y2
=x1x2+(2-mx1)(2-mx2)/n²
=x1x2+[4-2m(x1+x2)+m²x1x2]/n²
=[(m²+n²)x1x2-2m(x1+x2)+4]/n²
分子(m²+n²)x1x2-2m(x1+x2)+4
=2(2m²-8)/(4-3m²)+2m*4m/(4-3m²)+4
=(12m²-16)/(4-3m²)+4
=-4+4=0
∴OA·OB=0
即OA⊥OB