由f(-x)=ae^x+1/(ae^x)=f(x)=e^x/a+a/e^x
得a^2e^2x+1=e^2x+a^2
(a^2-1)(e^2x-1)=0
因此只能a^2-1=0
因a>0,故a=1
f(x)=e^x+1/e^x
x>0,e^x>1為增函數(shù),y=x+1/x在x>1時(shí)也為增函數(shù),
所以f(x)為增函數(shù).
已知函數(shù)f(x)=e^x/a+a/e^x(a>0)是R上的偶函數(shù),求a的值,證明函數(shù)f(x)在[0,+∞)上是增函數(shù).
已知函數(shù)f(x)=e^x/a+a/e^x(a>0)是R上的偶函數(shù),求a的值,證明函數(shù)f(x)在[0,+∞)上是增函數(shù).
數(shù)學(xué)人氣:569 ℃時(shí)間:2019-08-20 15:47:03
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