求證 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx
求證 1+2sinxcosx/sin^2x-cos^2x=sin^2x-cos^2x/1-2sinxcosx
數(shù)學(xué)人氣：882 ℃時(shí)間：2020-03-30 13:53:58
優(yōu)質(zhì)解答
1+2sinxcosx=sin²x+cos²x+2sinxcosx=(sinx+cosx)²sin²x-cos²x=(sinx+cosx)(sinx-cosx)則：(1+2sinxcosx)/(sin²x-cos²x)=(sinx+cosx)²/(sinx+cosx)(sinx-cosx)=(sinx+cosx)/...
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