設(shè)樣品中鋅的質(zhì)量為x;消耗硫酸溶液的質(zhì)量為y;
Zn+H2SO4=ZnSO4+H2↑
65 98 2
x y×9.8% 0.10g
65 |
x |
98 |
y×9.8% |
2 |
0.10g |
x=3.25g y=50g
(1)樣品中銅的質(zhì)量分數(shù)=
10g?3.25g |
10g |
(2)反應(yīng)所消耗的硫酸溶液質(zhì)量為y=50g;
(3)所得溶液的質(zhì)量為:3.25g+50g-0.1g=53.15g;
答:(1)樣品中銅的質(zhì)量分數(shù)為67.5%;
(2)消耗硫酸溶液的質(zhì)量為50g;
(3)所得溶液的質(zhì)量為53.15g;