你給的是一次函數(shù),請把題目寫清楚再來提問.
y=ax²+bx+c.兩個交點的話b²—4ac>0.一個交點b²—4ac=0.無交點b²—4ac
已知關(guān)于x的二次函數(shù)y=(2m-1)x+m^2+3m+4.請問:
已知關(guān)于x的二次函數(shù)y=(2m-1)x+m^2+3m+4.請問:
①m取何值時,函數(shù)圖象與x軸有兩個交點;
②m取何值時,函數(shù)圖象與x軸只有一個交點;
③m取何值時,函數(shù)圖象與x軸無交點.
錯了,二次函數(shù)應(yīng)是:y=-(2m-1)x+m^2+3m+4
①m取何值時,函數(shù)圖象與x軸有兩個交點;
②m取何值時,函數(shù)圖象與x軸只有一個交點;
③m取何值時,函數(shù)圖象與x軸無交點.
錯了,二次函數(shù)應(yīng)是:y=-(2m-1)x+m^2+3m+4
數(shù)學(xué)人氣:863 ℃時間:2019-09-17 08:11:47
優(yōu)質(zhì)解答
我來回答
類似推薦
- 已知關(guān)于x的二次函數(shù)y=x2-(2m-1)x+m2+3m+4. (1)探究m滿足什么條件時,二次函數(shù)y的圖象與x軸的交點的個數(shù); (2)設(shè)二次函數(shù)y的圖象與x軸的交點為A(x1,0),B(x2,0),且x12+x22=5,與y軸
- 已知關(guān)于x的二次函數(shù)y=x²-(2m-1)x+m²+3m+4.
- 已知關(guān)于x的二次函數(shù)y=x2-(2m-1)x+m2+3m+4. (1)探究m滿足什么條件時,二次函數(shù)y的圖象與x軸的交點的個數(shù); (2)設(shè)二次函數(shù)y的圖象與x軸的交點為A(x1,0),B(x2,0),且x12+x22=5,與y軸
- 已知關(guān)于X的二次函數(shù)Y=X*2-(2M-1)X+M*2+3M+4 PS:某某數(shù)*2的意思是這個數(shù)的平方,
- 函數(shù)y=(m^2-3m)x^(m^2-2m)+2是二次函數(shù),求m
- 已知實數(shù)x,y滿足2x+3y≤14,2x+y≤9,x≥0,y≥0,S=3x+ay,若S取得最大值時的最優(yōu)解有無窮多個,則實數(shù)a=?
- 請問這種成分還屬301不銹鋼嗎?(C-0.1003;Si-0.2467;Mn-2.2387;p-0.358;S-0.169;Cr-14.6342;Ni-6.0215)
- X=2*3*5*7*11*13*17*19*23*29*.N(N為質(zhì)數(shù)),求證:X+1為質(zhì)數(shù)
- 若√2007n是個非零整數(shù),則最小整數(shù)n是?
- Either I or he ( )soccer with Tom 四個選項 play are plays is
- .the music festival was great!Many famous people (attended) it.
- 如果(M)表示m的全部因數(shù)的和,如(4)=1+2+4=7,則(18)-(21)=()