f(x)=cosωx-sinωx-1
=√2cos(wx+π/4)-1
(1)T=2π/w=π/2解得w=4
2kπ-π
已知函數(shù)f(x)=cosωx-sinωx-1(ω＞0）的最小正周期為π/2.求：（1）ω的值.（2）函數(shù)f(x)的單調(diào)增區(qū)間
已知函數(shù)f(x)=cosωx-sinωx-1(ω＞0）的最小正周期為π/2.求：（1）ω的值.（2）函數(shù)f(x)的單調(diào)增區(qū)間
數(shù)學(xué)人氣：291 ℃時(shí)間：2019-10-11 09:51:14
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