√3a=2csinA
a/c=2sinA / √3
∵ a/c=sinA / sinC (正弦定理)
∴sinC=√3 /2
∠C=π/3
∵ c=√3
∴根據(jù)正弦定理,a/sinA =b/sinB=c/sinC=√3 /(√3/2)=2
∴a=2sinA ,b=2sinB ,
A+B=π-C=π-π/3=2π/3
∴B=2π/3-A
a+b+c=2(sinA+sinB)+√3
=2[sinA+sin(2π/3-A)]+√3
=2√3sin(A+π/6)+√3
∵ABC是銳角三角形
∴π/6