證明:
∵AB=AC,∠BAC=120°
∴∠B=∠C=30°
∵AD⊥AB
∴∠BAD=90°
∴∠ADB=60°
同理可得∠AED=60°
∴∠EAD=60°
即∠AED=∠ADE=∠DAE
∴△ADE是等邊三角形
如圖,AB=AC,∠BAC=120°,AD⊥AB,AE⊥AC,求證△ADE是等邊三角形
如圖,AB=AC,∠BAC=120°,AD⊥AB,AE⊥AC,求證△ADE是等邊三角形
數(shù)學(xué)人氣:261 ℃時間:2020-05-20 20:27:37
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