求dy/dx=x+xy^/y+yx^滿足初始條件y|(下面是x=0)=2的特解.
求dy/dx=x+xy^/y+yx^滿足初始條件y|(下面是x=0)=2的特解.
^是2,2次方
^是2,2次方
數(shù)學(xué)人氣:976 ℃時間:2020-05-11 21:17:22
優(yōu)質(zhì)解答
dy/dx = (x+xy²)/(y+yx²)(y+yx²)dy = (x+xy²)dxydy + yx²dy - xdx - xy²dx = 0ydy - xdx + 1/2 * (x²dy² - y²dx²) = 0dy² - dx² + x²dy² - ...
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