SN=根號2xSN-1
sn/sn-1=根號2（n》2）
所以sn是以s1為首相公比根號2的等比數(shù)列
s1=2
s2=2根號2
sn=2^((n+1)/2)
若數(shù)列{an}的前n項和Sn,a1=2,點(根號下Sn,根號下Sn-1)（n大于等于2）在直線x-根號2y=0上,求sn
若數(shù)列{an}的前n項和Sn,a1=2,點(根號下Sn,根號下Sn-1)（n大于等于2）在直線x-根號2y=0上,求sn
數(shù)學(xué)人氣：667 ℃時間：2019-12-16 00:47:04
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