首先,可以很輕松地寫(xiě)出通項(xiàng)公式a n=10^n-1
所以,Sn=10-1+10²-1+10³-1+……+10^n-1
=10(1-10^n)÷(1-10)-n
=[10^(n+1)-10]/9-n.
數(shù)列9,99,999,9999,.的前n項(xiàng)和=
數(shù)列9,99,999,9999,.的前n項(xiàng)和=
數(shù)學(xué)人氣:466 ℃時(shí)間:2019-12-11 05:48:07
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