而log2a2+log2a4+log2a6+log2a8+log2a10=
| log | a2?a4?a6?a8?a10 2 |
| log | (aq5)52 |
| log | 252 |
故答案為5
在等比數(shù)列{an}中，an＞0，（n∈N+）且a3a6a9=8，則log2a2+log2a4+log2a6+log2a8+log2a10=_．
在等比數(shù)列{an}中，an＞0，（n∈N+）且a3a6a9=8，則log2a2+log2a4+log2a6+log2a8+log2a10=______．
數(shù)學(xué)人氣：708 ℃時(shí)間：2020-05-16 21:04:11
優(yōu)質(zhì)解答
設(shè)等比數(shù)列的首項(xiàng)為a，公比為q，則a3a6a9=aq2?aq5?aq8=a3?q15=（aq5）3=23=8，得aq5=2；
而log2a2+log2a4+log2a6+log2a8+log2a10=
=
=
=5
故答案為5
而log2a2+log2a4+log2a6+log2a8+log2a10=
故答案為5
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