已知數(shù)列{an}滿足a1=1,an+1·an=2^n 則s2012
已知數(shù)列{an}滿足a1=1,an+1·an=2^n 則s2012
數(shù)學(xué)人氣：920 ℃時(shí)間：2020-04-16 11:06:33
優(yōu)質(zhì)解答
我來(lái)幫你解答吧!O(∩_∩)O~ 由an+1·an=2^n,可得an+2·an+1=2^（n+1）,兩者相除,可得an+2/an=2,觀察此式,可以發(fā)現(xiàn),數(shù)列{an}的奇數(shù)項(xiàng)和偶數(shù)項(xiàng)分別成等比數(shù)列,又a1=1,an+1·an=2^n,可以求出a2=2,則 數(shù)列{an}...
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